Run ID | Author | Problem | Lang | Verdict | Score | Time | Memory | Code Length | Submit Time |
---|---|---|---|---|---|---|---|---|---|
2547 | 陈颖钧 | 津津的储蓄计划 | C++ | Wrong Answer | 0 | 0 MS | 260 KB | 437 | 2024-12-15 17:36:26 |
#include<bits/stdc++.h> using namespace std; int main(){ int n,i,a,b=0; for(i=1;i<=12;i++){ cin>>n; b+=300; if((b-n)%100==0){ a+=(b-n)/100; b-=(b-n)/100; }else if((b-n)%100>0){ a+=(b-n)/100; b-=(b-n)%100; }else{ b-=b-n; } } if(b==0){ cout<<b+a*100+a*100*0.2; }else{ cout<<b; } }