Run ID | 作者 | 问题 | 语言 | 测评结果 | 分数 | 时间 | 内存 | 代码长度 | 提交时间 |
---|---|---|---|---|---|---|---|---|---|
8192 | admin | 分解质因数 | C++ | 通过 | 100 | 349 MS | 264 KB | 636 | 2025-03-28 17:45:47 |
using namespace std; int zs(int n){ for (int i = 2;i*i<=n;i++){ if (n % i==0){ return 0; } } return 1; } int main(){ int n,m; cin>>n>>m; for (int i = n;i<=m;i++){ int d = 0; for (int j = 2;j<i;j++){ if (i % j == 0){ d = 1; break; } } if (d == 0){ cout<<i<<"="<<i<<endl; } else{ cout<<i<<"="; int k = 2; int c = i; while (1){ while (c % k == 0 && zs(k)){ cout<<k; c = c / k; if (c != 1) cout<<"*"; } if (c == 1) { cout<<endl; break; } k++; } } } return 0; }
exit code: 0, checker exit code: 0
exit code: 0, checker exit code: 0
exit code: 0, checker exit code: 0
exit code: 0, checker exit code: 0
exit code: 0, checker exit code: 0
exit code: 0, checker exit code: 0
exit code: 0, checker exit code: 0
exit code: 0, checker exit code: 0
exit code: 0, checker exit code: 0
exit code: 0, checker exit code: 0