Run ID | 作者 | 问题 | 语言 | 测评结果 | 分数 | 时间 | 内存 | 代码长度 | 提交时间 |
---|---|---|---|---|---|---|---|---|---|
9542 | A班-许锘林 | 求最大总和 | C++ | 通过 | 100 | 2 MS | 268 KB | 365 | 2025-04-17 20:22:21 |
using namespace std; int main() { int n; cin>>n; int a[n]; int b[n]; for(int i = 0;i < n;i++) { cin>>a[i]>>b[i]; } sort(a,a + n); int min = a[n - 1]; int Min = b[0]; for(int i = 0;i < n;i++) { if(b[i] >= min && b[i] <= Min) { Min = b[i]; } } cout<<"["<<min<<","<<Min<<"]"<<endl; return 0; }
exit code: 0, checker exit code: 0
exit code: 0, checker exit code: 0
exit code: 0, checker exit code: 0
exit code: 0, checker exit code: 0
exit code: 0, checker exit code: 0