提交时间:2024-12-07 10:49:18

运行 ID: 1589

#include <bits/stdc++.h> using namespace std; int main() { for(int i = 1000;i <= 9999;i++) { int ge = i % 10; int shi = i / 10 % 10; int bai = i / 100 % 10; int qian = i / 1000; int k = ge + shi; int s = bai + qian; if(k % 2 == 0 && s % 2 == 1 && k > s && i % 8 == 0) { cout<<i<<endl; } } return 0; }